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Re: Evaluating a series
From: |
Martin Helm |
Subject: |
Re: Evaluating a series |
Date: |
Thu, 09 Aug 2012 13:40:52 +0200 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:14.0) Gecko/20120713 Thunderbird/14.0 |
Am 09.08.2012 09:30, schrieb Søren Hauberg:
> On Aug 9, 2012, at 9:22 AM, address@hidden wrote:
>
>> Please assist me to do this:
>> Evaluate the series
>>
>> 1-1/3+1/5-1/7+1/9-...+1/1001
> You can get the positive part of the sequence by doing something like
>
> 1 ./ (1:4:1001)
>
> summing that will give you part of your result. You can do the same for the
> negative part and subtract that from the positive part.
>
> Søren
>
I have not thought very deeply about it, but wouldn't it be more stable
to group every pair of differences together
1/n - 1/(n+2) = 2/( n*(n+2) ) so that only positive numbers are summed
and no subtractions take place?
Just a thought without details, since that sounds like homework somehow
(i also matters in which order the summation is done, not really for
this small example).
- Evaluating a series, duncan . kavu, 2012/08/09
- Re: Evaluating a series, Søren Hauberg, 2012/08/09
- Re: Evaluating a series,
Martin Helm <=
- Re: Evaluating a series, Nicholas Jankowski, 2012/08/09
- Re: Evaluating a series, Jordi Gutiérrez Hermoso, 2012/08/09
- Re: Evaluating a series, Jordi Gutiérrez Hermoso, 2012/08/09
- Re: Evaluating a series, Andy Buckle, 2012/08/09
- Re: Evaluating a series, Nicholas Jankowski, 2012/08/09
- Re: Evaluating a series, Jordi Gutiérrez Hermoso, 2012/08/09