Re: Evaluating a series

[Nicholas Jankowski]

On Thu, Aug 9, 2012 at 9:07 AM, Andy Buckle <address@hidden> wrote:
>
>
> On 9 August 2012 14:01, Nicholas Jankowski <address@hidden> wrote:
>>
>> On Thu, Aug 9, 2012 at 8:46 AM, Andy Buckle <address@hidden> wrote:
>> >
>> >
>> > On 9 August 2012 13:38, Jordi Gutiérrez Hermoso <address@hidden>
>> > wrote:
>> >>
>> >> On 9 August 2012 08:26, Nicholas Jankowski <address@hidden> wrote:
>> >> > On Thu, Aug 9, 2012 at 3:22 AM,  <address@hidden> wrote:
>> >> >> Please assist me to do this:
>> >> >> Evaluate the series
>> >> >>
>> >> >> 1-1/3+1/5-1/7+1/9-...+1/1001
>> >> >>
>> >> >
>> >> > While there may be more elegant ways to do this, you're basically
>> >> > trying to repeat an addition operation of items with changing value.
>> >>
>> >> e.g.
>> >>
>> >>     sum(1./(1:4:1001) - 1./(3:4:1001))
>> >>
>> >> ?
>> >>
>> >> - Jordi G. H.
>> >> _______________________________________________
>> >> Help-octave mailing list
>> >> address@hidden
>> >> https://mailman.cae.wisc.edu/listinfo/help-octave
>> >
>> >
>> >>sum(1./(1:4:1001) - 1./(3:4:1001))
>> > error: operator -: nonconformant arguments (op1 is 1x251, op2 is 1x250)
>> > error: evaluating argument list element number 1
>> >>sum(1./(1:4:1001)) - sum(1./(3:4:1001))
>> > ans =  0.78590
>> >
>> > --
>> > /* andy buckle */
>>
>> 50 points from Gryffindor: for doing the kid's homework for him
>> instead of leading him to actually learning to use the program.
>
>
> I would not have posted the answer had Jordi not almost posted the answer...
>
> --
> /* andy buckle */

nah... it's like every other academic paper. you deliberately leave
one or two typo's in the equations to force the grad students
'reimplementing' your work to re-derive the equations themselves :)