
From:  Thomas Shores 
Subject:  Re: Solving functional nonlinear equation 
Date:  Mon, 28 Dec 2009 16:50:30 0600 
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Disregard my last post. I misread the problem. However, I'm a bit
puzzled by the delay. This file, test.m tic; x=linspace(.1,1,160); y=x; [xx,yy]=meshgrid(x,y); for a = [1.1,1.2,1.5,2] b=1/a;zz=b*(xx.*yy).^(b1)+xx.^(b1)+yy.^(b1); figure; surf(xx,yy,zz);shading interp;fflush(1); end toc; gave this result on my system (Octave 3.2.3, gnuplot4.2), and of course produced the plots: octave:1> test Elapsed time is 1.49368 seconds. octave:2> On 12/28/2009 02:55 PM, Thomas Shores wrote: If your objective is to do some plotting of f(x,y) in the xydomain, read the comments that followed your post. If it is to solve the equation, do a bit of formal algebra: you say that a is a positive parameter. Make the substitution b=1/a. If you want to avoid complex variables, restrict the domain to x, y>=0. If y=0, than any choice of a,x will solve the equation. If y>0, cancel y from the equation to obtain b*x^(b1)  1=0. Thus y is irrelevant. Now if you want a plot in xbdomain, follow Chang's suggestions along the lines of 
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