Re: about axes properties

[abdominales]

Hi,
I would want to write a vector that begins in one certain  point, so my idea
was using the function compass and changing the position of the origin of
the axes. But it doesn't work, always draw the vector(arrow) emergin from
the same origin.

¿have you got any idea?

Thanks.

Matthias Brennwald (bwm) wrote:
> 
> On Wed, 2008-07-23 at 11:26 -0500, address@hidden wrote:
>> Message: 8
>> Date: Wed, 23 Jul 2008 18:25:10 +0200
>> From: Francesco Potorti` <address@hidden>
>> Subject: about axes properties
>> To: Octave users list <address@hidden>
>> Message-ID: <address@hidden>
>> Content-Type: text/plain; charset=iso-8859-1
>> 
>> In the 3.0 manual, I read exactly the same description for both the
>> "position" and "outerposition" properties.
>> 
>> Also, while plotting two graphs in two subplots, I see that I can move
>> them around using "outerposition", while changing "position"
>> apparently
>> has no effect.
>> 
>> Guessing the right numbers for "outerposition" is a matter of trying.
>> Can someone shed some light on these misteries?
> 
> My understanding is that the parameter for outerposition is a vector
> p(1,2,3,4) with:
> 
> p(1) is the x-coordinate of the lower left corner of the plot
> p(2) is the y-coordinate of the lower left corner of the plot
> p(3) is the width of the plot
> p(4) is the height of the plot
> 
> All these values are given in relative units, i.e. in fractions of the
> width and height of the graph window, where (0/0) is the lower left
> corner of the window and (1/1) is the upper right corner.
> 
> Does that make sense? If so, something along these lines should propably
> be added to the documentation.
> 
> Matthias
> 
> -- 
> Matthias Brennwald
> Project Manager Safety Analysis
> Nagra, 5430 Wettingen, Switzerland
> +41 56 437 13 32
> 
> _______________________________________________
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> 
> 

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