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Uniform partition of an interval
From: |
John W. Eaton |
Subject: |
Uniform partition of an interval |
Date: |
Wed, 17 May 2000 03:30:59 -0500 (CDT) |
On 17-May-2000, address@hidden <address@hidden> wrote:
| Hello!
|
| What is the MAIN reason that 1.8:0.05:1.9 produces [1.8000 1.8500]
| and not [1.8000 1.8500 1.9000]?
| I am using 2.0.14 version of Octave.
| Thank you for your answer.
| Best regards,
| Emil Zagar
I'd guess that the MAIN reason is that there is a bug in the way
Octave is trying (very hard) to compute the correct number of elements
for ranges. If you're in a debugging mood, the code to look at is in
the Range::nelem_internal and related functions in liboctave/Range.cc.
jwe
--
www.che.wisc.edu/octave | Thanking you in advance. This sounds as if the
www.che.wisc.edu/~jwe | writer meant, "It will not be worth my while to
| write to you again." -- Strunk and White
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Re: Uniform partition of an interval, Francesco Potorti`, 2000/05/17