[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Uniform partition of an interval
From: |
emil |
Subject: |
Uniform partition of an interval |
Date: |
Wed, 17 May 2000 10:25:18 +0200 (CEST) |
Hello!
What is the MAIN reason that 1.8:0.05:1.9 produces [1.8000 1.8500]
and not [1.8000 1.8500 1.9000]?
I am using 2.0.14 version of Octave.
Thank you for your answer.
Best regards,
Emil Zagar
-----------------------------------------------------------------------
Octave is freely available under the terms of the GNU GPL.
Octave's home on the web: http://www.che.wisc.edu/octave/octave.html
How to fund new projects: http://www.che.wisc.edu/octave/funding.html
Subscription information: http://www.che.wisc.edu/octave/archive.html
-----------------------------------------------------------------------
- Uniform partition of an interval,
emil <=
Re: Uniform partition of an interval, Francesco Potorti`, 2000/05/17