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Re: [Gnewsense-dev] Re: [gNewSense-users] possible error in gen-kernel b


From: Tony
Subject: Re: [Gnewsense-dev] Re: [gNewSense-users] possible error in gen-kernel builder script
Date: Tue, 18 Aug 2009 23:27:18 +1000
User-agent: Thunderbird 2.0.0.22 (X11/20090608)

That proposed regex is syntactically incorrect, I believe.

It does not close the \( with a corresponding \)

However. since this has not previously worked, I would be wary of "fixing" it. We are not aware of why there is a need to append lines with a ? in the files matching

debian/d-i/modules/*

Change mgt tells me this may break things in all sorts of new and unusual ways.

I vote to leave it "broken" until further information is to hand.

Cheers,

gurrier





Karl Goetz wrote:
On Sat, 15 Aug 2009 16:11:31 +0200
Sam Geeraerts <address@hidden> wrote:

Kemmey, Whitney W CIV NSWCDD, K54 schreef:
The gen-kernel builder script includes the following lines:

    # Changes so it'll compile without some modules
    for i in debian/d-i/modules/*; do
        sed -i 's/^\([[^ ?][^ ?]*\)$/\1 ?/' $i
    done

Is the sed command correct?  I think this is meant to look for
every line that contains no spaces or question marks and append
" ?" to the end of the line.  My regular expression skills aren't
great, but I think it should be:

        sed -i 's/^\([^ ?][^ ?]*\)$/\1 ?/' $i

(Removed the first square bracket.)  Without this change, I think
it's expecting the first character to be "[", "^", " ", or "?",
which I think is incorrect.

Can anyone clarify?
(Moving to -dev.)

You're probably right that the regular expression is wrong. Your correction seems logical, but don't know what the sed script is
actually for. I suppose it's to ensure that every module in
debian/d-i/modules/* has a question mark behind it. However, I
haven't been able to figure out what that means and if that's
necessary.

I've run the sed script off a mate. It seems that the [ is misplaced,
assuming we are correct about what the script is meant to do.

his regex is `sed -i 's/^\([^ ?]+$/\1 ?/' $i`

(Afaik its the same as that proposed above)
kk

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