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Re: [PATCH v2] vl/s390: fixup ram sizes for compat machines
From: |
David Hildenbrand |
Subject: |
Re: [PATCH v2] vl/s390: fixup ram sizes for compat machines |
Date: |
Wed, 1 Apr 2020 14:04:17 +0200 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:68.0) Gecko/20100101 Thunderbird/68.6.0 |
> something like
>
> while ((sz >> increment_size) > MAX_STORAGE_INCREMENTS) {
> increment_size++;
> }
> newsz = sz >> increment_size << increment_size;
>
> if (sz != newsz) {
> qemu_printf("Ram size %" PRIu64 "MB was fixed up to %" PRIu64
Maybe warn_report()
> "MB to match machine restrictions. Consider updating "
> "the guest definition.\n",
> sz / MiB, newsz / MiB);
might be able to squeeze that into the previous line.
> }
> return newsz;
>
> ?
Much better.
>>
>>
>>> if (ret == -E2BIG) {
>>> error_setg(&err, "host supports a maximum of %" PRIu64 " GB",
>>> hw_limit / GiB);
>>> @@ -361,27 +361,20 @@ out:
>>> static void sclp_memory_init(SCLPDevice *sclp)
>>> {
>>> MachineState *machine = MACHINE(qdev_get_machine());
>>> + MachineClass *machine_class = MACHINE_GET_CLASS(qdev_get_machine());
>>> ram_addr_t initial_mem = machine->ram_size;
>>> int increment_size = 20;
>>>
>>> /* The storage increment size is a multiple of 1M and is a power of 2.
>>> - * The number of storage increments must be MAX_STORAGE_INCREMENTS or
>>> fewer.
>>> + * For some machine types, the number of storage increments must be
>>> + * MAX_STORAGE_INCREMENTS or fewer.
>>> * The variable 'increment_size' is an exponent of 2 that can be
>>> * used to calculate the size (in bytes) of an increment. */
>>> - while ((initial_mem >> increment_size) > MAX_STORAGE_INCREMENTS) {
>>> + while (machine_class->fixup_ram_size != NULL &&
>>> + (initial_mem >> increment_size) > MAX_STORAGE_INCREMENTS) {
>>> increment_size++;
>>> }
>>> sclp->increment_size = increment_size;
>>
>> IIRC one could define ram size in KB. Not sure if it is worth checking
>> against that.
>> [...]
>
> If this is not aligned to 1MB, that would already fail when registering the
> memslot, I think.
True, not sure how cryptic the error will be :)
LGTM
--
Thanks,
David / dhildenb