Re: Preserving signbit for range operator

[Daniel J Sebald]

On 02/25/2013 02:45 PM, Michael D. Godfrey wrote:
> On 02/25/2013 03:37 PM, Daniel J Sebald wrote:
> > octave:6> [0:-3:-5]
> > ans =
> >
> > 0 -3
> But:
> octave:3> [-0:-3:-5]
> ans =
>
> -0 -3
>
> Symmetry of any interest?

Symmetry is tough simply because IEEE specification doesn't have a +0, 
but the alternate output you give is technically the correct result by 
definition.  [a:z:b] for [-0:-3:-5] means a=-0; the result should be -0 
-3.  But for [0:-3:-5] the result is 0 -3.

Currently, it is this Octave result

octave:28> [-0:3:5]
ans =

   0   3

which is not abiding by the definition.

Dan