Re: Preserving signbit for range operator

[Daniel J Sebald]

On 02/25/2013 02:48 PM, Daniel J Sebald wrote:
> On 02/25/2013 02:37 PM, Daniel J Sebald wrote:
>
> > PS: A bit arbitrary, but this result
>
> Sorry, forgot to erase that bit. I was going to inquire about the result
>
> octave:25> [1:0:1]
> ans = [](1x0)
>
> where the increment is zero. Technically, one could argue [a:0:b] = a.
> That is, there may be an infinite number of integer values K for which
> a+K*0 < b, but all values of a+K*0 are a. Arbitrary choice I suppose.

^^^^^^^^^^^^^

a+K*0 <= b

Dan