Re: [igraph] Re: alpha in power.law.fit

[Simone Gabbriellini]

Thanks Gabor,

btw, is it correct to assume that the k parameter is equal to alpha-1?

simone

2009/3/5 Gábor Csárdi <address@hidden>:
> Yep, coef(fit) is slightly better, as it likely works with the results
> of many kind of fitting functions.
>
> Best,
> G.
>
> On Thu, Mar 5, 2009 at 5:20 PM, Simone Gabbriellini
> <address@hidden> wrote:
>> SOLVED...
>>
>> it was easy...
>>
>>> fit<-power.law.fit(x)
>>> address@hidden
>>   alpha
>> 1.754803
>>
>> best regards,
>> simone
>>
>> 2009/3/5 Simone Gabbriellini <address@hidden>:
>>> hi list,
>>>
>>> I'd like to use the alpha coefficient I've found with power.law.fit(),
>>> but I am not able to extract it from the mle object... what is the
>>> right sintax?
>>>
>>> I need it in order to plot the distribution with:
>>>
>>> plot(ppareto(table(my.data.frame$score), location=alpha, shape=
>>> alpha-1), type="p")
>>>
>>> thanks,
>>> simone
>>>
>>
>>
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>
>
>
> --
> Gabor Csardi <address@hidden>     UNIL DGM
>
>
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