List question

[Teemu Ikonen]

Is list-element subindexing implemented in Octave 2.1?

In matlab the following works:
>>  l = {ones(2,2), zeros(2,2), hilb(2)}    
l = 
    [2x2 double]    [2x2 double]    [2x2 double]
>> l{3}(1,2)
ans =
    0.5000

The same in octave fails:
octave:9> l = {ones(2,2), zeros(2,2), hilb(2)}
l =

  [1,1] =

    1  1
    1  1

  [1,2] =

    0  0
    0  0

  [1,3] =

    1.00000  0.50000
    0.50000  0.33333

octave:10> l{3}(1,2)
error: invalid column index = 2

Any plans of fixing this? Of course I could copy the matrix to a temp
variable and then access the matrix element but that's really
unelegant...

Teemu




-----------------------------------------------------------------------
Octave is freely available under the terms of the GNU GPL.

Octave's home on the web:  http://www.che.wisc.edu/octave/octave.html
How to fund new projects:  http://www.che.wisc.edu/octave/funding.html
Subscription information:  http://www.che.wisc.edu/octave/archive.html
-----------------------------------------------------------------------