Re: a=0; a([1,1])++ -> a == 2

[Etienne Grossmann]

  Hello,

========================================

  a=0; b = a([1,1])++ ;

should be equivalent to

  a=0; b=a([1,1]); a([1,1])=a([1,1])+1;

whereas 

  a=0; b = ++a([1,1]) ;

should be equivalent to 

  a=0; a([1,1])=a([1,1])+1; b=a([1,1]);

=======================================

  You are right; I was confusing infix ++ and postfix ++.

  Etienne



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