a=0; a([1,1])++ -> a == 2

[Etienne Grossmann]

  Hello,

  sorry if the answer to my question is a clear-cut "no" or if it has
already been discussed.

  Wouldn't it make sense to have the code 

       a=0; b = a([1,1])++ ;

  be equivalent to either

       a=0; b=a([1,1]); b++; for i in [1,1], a(i)++ ; end

       yielding       a == 2, b == [1;1]
  or 
       a=0; b=zeros(size(a)); for i in [1,1], b(i) = a(i)++ ; end
    
       yielding       a == 2, b == [1;2]


  The current behavior yields :

      a == 1, b == [1;1]

  My motivation is that I would like not to do :

      for i = indices, a(i)++ ; end

  Cheers,

  Etienne



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