Dear Octave/Matlab expert:
. We know the inver fourier transform of sinc is a rectangular funciton
We know 
As 
So
my following code try to do so in matlab student verson 5.3,
f=-128:128;
y=((sin(pi*f)/(pi*f)))
t=-1:2/256;1;
fe=length(t);
Y=ifft(y,256);
plot(t,Y(1:fe));
Warning: Imaginary parts of complex X and/or Y arguments ignored.
diary off
but my output fig graph is not so , it just is a horizontal straight line on value 0. What may cause wrong?
attach microsoft word file to little bit describe basic math of my discussion.
need and hope to see your help again soon
Eric(address@hidden)
