Re: How to preserve $-containing terms in an expanded variable (with call)?

[John Graham-Cumming]

Dimitry Golubovsky wrote:
> Namely, the $(call myvar,foo) must expand into:
>
> awk '$0 != foo { ... }'
>
> where $0 is in the awk sense (i. e. whole line read from the input).
>
> I tried to define myvar like this:
>
> myvar = awk '$$0 != $(0) { .... }'
>
> this does not work: $$0 expands to /bin/sh i. e. shell's $0, not awk's

Firstly, if you define

    myvar = awk '$$0 != $0 { ... }'

and then look at the value of $(call myvar,foo) it IS what you want, namely:

    awk '$0 != foo { ... }'

(You can verify this with $(warning $(call myvar,foo)))

Secondly, I tried doing $(shell $(call myvar,foo)) and I saw that the 
shell was being asked to execute awk '$0 != foo { ... }'.

So what's the issue that you are seeing, exactly?  I think it would be 
helpful to post a full example, e.g. show the definition of your 
variable, and exactly how you are using it.

John.
--
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