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| From: | lina |
| Subject: | Re: [Help-bash] how to understand the xargs |
| Date: | Tue, 27 Dec 2011 23:35:22 +0800 |
| User-agent: | Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.2.24) Gecko/20111114 Icedove/3.1.16 |
On Tuesday 27,December,2011 11:31 PM, Greg Wooledge wrote:
On Tuesday 27,December,2011 11:16 PM, Greg Wooledge wrote:i=$((i+1))On Tue, Dec 27, 2011 at 11:27:35PM +0800, lina wrote:i=$(i+1)$(...) is command substitution. $((...)) is arithmetic substitution.
This is a core part, well, why not it showed me nothing, after run it? Thanks ahead,
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