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Re: [Help-bash] how to understand the xargs
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From: |
Greg Wooledge |
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Subject: |
Re: [Help-bash] how to understand the xargs |
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Date: |
Tue, 27 Dec 2011 10:31:43 -0500 |
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User-agent: |
Mutt/1.4.2.3i |
> On Tuesday 27,December,2011 11:16 PM, Greg Wooledge wrote:
> > i=$((i+1))
On Tue, Dec 27, 2011 at 11:27:35PM +0800, lina wrote:
> i=$(i+1)
$(...) is command substitution.
$((...)) is arithmetic substitution.
- [Help-bash] how to understand the xargs, lina, 2011/12/27
- Re: [Help-bash] how to understand the xargs, lina, 2011/12/27
- Re: [Help-bash] how to understand the xargs, Greg Wooledge, 2011/12/27
- Re: [Help-bash] how to understand the xargs, lina, 2011/12/27
- Re: [Help-bash] how to understand the xargs, Greg Wooledge, 2011/12/27
- Re: [Help-bash] how to understand the xargs, lina, 2011/12/27
- Re: [Help-bash] how to understand the xargs,
Greg Wooledge <=
- Re: [Help-bash] how to understand the xargs, lina, 2011/12/27
- Re: [Help-bash] how to understand the xargs, Greg Wooledge, 2011/12/27
- Re: [Help-bash] how to understand the xargs, lina, 2011/12/27
Re: [Help-bash] how to understand the xargs, Dan Douglas, 2011/12/28