On Friday 12 February 2010 18:45:01, Michael Snyder wrote:
Paragi, Ajeykumar B wrote:
Hi,
I have invoked gdb with '-e' command line option on an executable,
The gdb manual says '-e' is used to set the executable to run.
But I could not see the symbols read in by gdb when I use -e and could
not insert breakpoints.
What is the intent of having the command line option "-e" or "-exec"?
Hmmm, it does seem to be broken.
It's not. `-e' is equivalent to "(gdb) exec-file". It doesn't read
its argument for symbols, only for executable to run, or for pure
memory contents.
You can get the same effect, though, by just leaving out the -e flag.
% gdb my-executable
That's equivalent to "(gdb) file", which is equivalent to
"gdb -e my-executable -s my-executable", or just "gdb -se my-executable".