Re: gdb command line option -e or -exec usage

[Pedro Alves]

On Friday 12 February 2010 18:45:01, Michael Snyder wrote:
> Paragi, Ajeykumar B wrote:
> > Hi,
> > 
> > I have invoked gdb with '-e' command line option on an executable, 
> > The gdb manual says '-e' is used to set the executable to run.
> > But I could not see the symbols read in by gdb when I use -e and could
> > not insert breakpoints.
> > 
> > What is the intent of having the command line option "-e" or "-exec"?
> 
> Hmmm, it does seem to be broken.

It's not.  `-e' is equivalent to "(gdb) exec-file".  It doesn't read
its argument for symbols, only for executable to run, or for pure
memory contents.

> 
> You can get the same effect, though, by just leaving out the -e flag.
> 
>      % gdb my-executable

That's equivalent to "(gdb) file", which is equivalent to
"gdb -e my-executable -s my-executable", or just "gdb -se my-executable".

-- 
Pedro Alves