Re: Should not * be greedy in a regexp?

[Stefan Monnier]

> Should not both this regexp give the same result here? It looks to me like *
> is treated as *? - ie non-greedy.

The regexp-matching is greedy, so it matches the longest match, but the
regexp-search will return the leftmost (i.e. first) match, so mod-regx*
will match at the very first position (matching the mprty string),
whereas mod-regx+ will fail at that position so it will then succeed at
the second position where both mod-regx+ and mod-regx* would match the
same string.


        Stefan