Re: Should not * be greedy in a regexp?

[Lennart Borgman (gmail)]

Andreas Schwab wrote:
> Andreas Schwab <address@hidden> writes:
>
> > "Lennart Borgman (gmail)" <address@hidden> writes:
> >
> > > Starting from
> > >
> > >    emacs -Q
> > >
> > > Put this in the *scratch* buffer and eval it:
> > >
> > > (let* ((mod-regx+ "\\(\\(?:[CSM]-\\)+\\)")
> > >        (mod-regx* "\\(\\(?:[CSM]-\\)*\\)")
> > >        (str "<C-S-tab>")
> > >        (m+ (when (string-match mod-regx+ str)
> > >              (match-string 0 str)))
> > >        (m* (when (string-match mod-regx* str)
> > >              (match-string 0 str))))
> > >   (lwarn 't :warning "m+=%s, m*=%s" m+ m*))
> > >
> > > I get
> > >
> > >   Warning (t): m+=C-S-, m*=
> > >
> > > Should not both this regexp give the same result here? It looks to me like
> > > * is treated as *? - ie non-greedy.
> > The regexp matches the empty string.
>
> ... at the start of the string, I wanted to add.

Ah, thanks.