Re: Calc: `*' binds more strongly than `/'

[Stefan Monnier]

> The reason for Calc's current behavior is because Dave Gillespie,
> Calc's author, thought of "a b / c d" as representing 

I expect the reason is slightly different: it's that the same rule is used
for "a * b / c * d" as for "a b / c d".  The "juxtaposition operator" is
traditionally assumed to have the highest precedence, so it of course parses
as "(a b)/(c d)".


        Stefan