Re: A question about read syntax and compiled backreferences

[Stuart D. Herring]

> If it avoids the circle, it presumably also detects it.  Why can't it
> throw an error then instead of producing output that can't be read in
> again?

Sometimes it neither avoids the circle nor fails, yet produces wrong output:

(let* ((x (vector)) (y (cons x x))) (princ y))

just prints ([] . []), and the reader will not generate two `eq' vectors
from reading this.

Davis

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