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GNU Parallel Bug Reports Parallel as for (no argument)
From: |
Hadrien Lacour |
Subject: |
GNU Parallel Bug Reports Parallel as for (no argument) |
Date: |
Sat, 29 Oct 2016 12:43:12 +0200 |
User-agent: |
Mutt/1.5.24 (2015-08-30) |
Hello,
I'm tryin to replace
for i in $(seq 5); do seq 5 | parallel -j1 --eta 'sleep 1; echo'; done
with a full parallel workflow but I can't figure how to do it. I tried
seq 5 | parallel -j1 -N0 'seq 5 | parallel -j1 --eta "sleep 1; echo"'
thinking that the N0 could do the trick, but the result isn't the same. Is
there a way to do it?
- GNU Parallel Bug Reports Parallel as for (no argument),
Hadrien Lacour <=