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Re: Incorrect alias expansion within command substitution


From: Alex fxmbsw7 Ratchev
Subject: Re: Incorrect alias expansion within command substitution
Date: Wed, 2 Feb 2022 15:04:33 +0100

ive had many inconsistency with bash this regarding exoerienced

On Wed, Feb 2, 2022, 15:00 L A Walsh <bash@tlinx.org> wrote:

> On 2022/01/31 20:40, Martijn Dekker wrote:
> > On the latest code from the devel branch:
> > GNU bash, versie 5.2.0(35)-alpha (x86_64-apple-darwin18.7.0)
> >
> > Reproducer script:
> >
> > shopt -s expand_aliases
> > alias let='let --'
> > set -x
> > let '1 == 1'
> > : $(let '1 == 1')
> >
> > Output:
> >
> > + let -- '1 == 1'
> > ++ let -- -- '1 == 1'
> > foo: line 5: let: --: syntax error: operand expected (error token is "-")
> > + :
> >
> > The alias is incorrectly expanded in the command substitution,
> > duplicating the '--' argument and causing a syntax error.
> >
> ----
> I can't say for sure, but it would be interesting if anyone else
> has this result in a bash with aliases on by default:
>
> I.e. My bash is posix compliant by default w/r/t aliases:
> >  env -i /bin/bash --noprofile --norc
> bash-4.4$ shopt -p expand_aliases
> shopt -s expand_aliases
>
> and it doesn't show the above error:
>
> bash-4.4$ alias let='let --'
> bash-4.4$ set -x
> bash-4.4$ let '1 == 1'
> + let -- '1 == 1'
> bash-4.4$ : $(let '1 == 1')
> ++ let -- '1 == 1'
> + :
>
> It may not be the case, but to me, looked like the alias for 'let' had
> been disabled
> in the $() subshell as per standard bash behavior of disabling aliases
> on startup.
>
> I.e. if you configure bash to be posix compliant w/r/t aliases on
> shell startup, this seems to fix the above problem.
>
>
>
>
>
>


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