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Re: kerberos telnet?
From: |
Simon Josefsson |
Subject: |
Re: kerberos telnet? |
Date: |
Mon, 23 Sep 2002 12:48:33 +0200 |
User-agent: |
Gnus/5.090008 (Oort Gnus v0.08) Emacs/21.2 (i386-debian-linux-gnu) |
Sergey Poznyakoff <address@hidden> writes:
>> I am running from inetutils CVS with Heimdal header files, but there
>> seem to be some name space collision:
>
> I see. Indeed, Heimdal declares its own Authenticator type. To
> avoid the clash, change to the inetutils libtelnet directory,
> run the following script and then recompile:
>
> #! /bin/sh
> for name in `grep -l Authenticator *.[ch]`
> do
> mv $name ${name}~
> sed 's/Authenticator/TN_Authenticator/g' ${name}~ > $name
> done
Thanks, a small step further, however:
gcc -DHAVE_CONFIG_H -I. -I. -I.. -I../include -g -O2 -c `test -f
'kerberos5.c' || echo './'`kerberos5.c
kerberos5.c: In function `encryption_init':
kerberos5.c:160: structure has no member named `enctype'
kerberos5.c:168: structure has no member named `keyblock'
kerberos5.c:172: structure has no member named `keyblock'
...
Looking at the code:
void
encryption_init (krb5_creds *creds)
{
krb5_keyblock *newkey = 0;
...
if (newkey)
{
switch (newkey->enctype)
{
case ENCTYPE_DES_CBC_CRC:
...
and in /usr/include/krb5.h reveals krb5_keyblock looks like this in
Heimdal:
typedef struct EncryptionKey {
int keytype;
octet_string keyvalue;
} EncryptionKey;
I will try to compile inetutils with MIT Kerberos instead, for my
purpose it will probably work equally well and will perhaps be easier
to get to work.
- kerberos telnet?, Simon Josefsson, 2002/09/12
- Re: kerberos telnet?, Sergey Poznyakoff, 2002/09/13
- Re: kerberos telnet?, Simon Josefsson, 2002/09/13
- Re: kerberos telnet?, Sergey Poznyakoff, 2002/09/13
- Re: kerberos telnet?, Simon Josefsson, 2002/09/13
- Re: kerberos telnet?, Sergey Poznyakoff, 2002/09/13
- Re: kerberos telnet?, Sergey Poznyakoff, 2002/09/13
- Re: kerberos telnet?, Simon Josefsson, 2002/09/17
- Re: kerberos telnet?, Sergey Poznyakoff, 2002/09/19
- Re: kerberos telnet?,
Simon Josefsson <=
- Re: kerberos telnet?, Simon Josefsson, 2002/09/23