Re: Synonym

[John W. Eaton]

On 4/8/20 11:46 AM, "Markus Mützel" wrote:

> I don't think it is necessary to initialize varargout. It should be initialized 
> to the correct length. [1]
> This should be enough:
>
> function varargout = short (varargin)
>    [varargout{:}] = verylongname (varargin{:});
> endfunction

Can you verify that this function actually works in Matlab (see below 
for simple example)?

> [1]: https://de.mathworks.com/help/matlab/ref/varargout.html

The example on this page uses

  [varargout{1:nargout}] = ...

which does work in Octave.  But

  [varargout{:}] = ...

fails in Octave unless varargout is explicitly initialized.

And there is another example on that page that shows this:

function varargout = variableNumInputAndOutput(varargin)
    disp(['Number of provided inputs: ' num2str(length(varargin))])
    disp(['Number of requested outputs: ' num2str(nargout)])

If varargout is initialized when the function is called, then why use 
length (varargin) instead of nargin and nargout instead of length 
(varargout)?

Can you try the following in Matlab to verify that varargout is initialized?

function varargout = xsvd (varargin)
  numel (varargin)
  numel (varargout)
  [varargout{:}] = svd (varargin{:});
end

and then call it with

  xsvd (rand (2))
  s = xsvd (rand (2))
  [u, s, v] = xsvd (rand (2))

Does that work?  If so, I'll fix Octave to match that behavior.

jwe