Re: find number position

[Anton Dereventsov]

The following works perfectly:
find (min (a))   

'find(min(a))' returns 1 since min(a) is a number, I think you meant 'find(a==min(a))', which returns 3.
You can also run '[m,im] = min(a)', which returns m = 4 (minimum), im = 3 (position of minimum).

Anton

On Fri, Oct 12, 2018 at 3:50 AM Pantxo <address@hidden> wrote:

turbofib wrote
> hi,
> i want to find lowest number position
> a=[5 18 4 nan]
> sort(a)
>
> 4 5 18 nan
>
> if i write :
>
> find(a==4) is not correct...i get  ans = 0
>
>
>
> how can i position lowest number? thank you
> --
> Sent from:
> http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html

Hi,

The following works perfectly:

find (min (a))

and

find (a==4)

returns 3, as expected.

Pantxo



--
Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html