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Re: building dynamic ranges from matrix


From: avlas
Subject: Re: building dynamic ranges from matrix
Date: Tue, 21 Nov 2017 19:01:18 -0500

El dimarts, 21 de novembre de 2017, a les 18:52:32 EST, AG va escriure:

  Thanks Doug. The range start end matrix is built dynamically at runtime and
  so the number of rows is unknown - could be 2 rows could be 10000.
  
  Do you have any idea how your solution might be generalize for an unknown
  number of rows at runtime?
  I tried using cell arrays as an intermediary. I was trying to put each rows
  ranges in a cell then joining all the ranges stored within the cell to the
  final vector but I can't seem to get it to work. Appreciate the help.
  
  
  
  --
  Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html
  
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Look arrayfun is very fast even for 10000 rows:

x = round(100*randn(10000,2));
tic,y = arrayfun(@(x,y) x:y, x(:,1), x(:,2), "UniformOutput", false);toc
Elapsed time is 0.0658202 seconds.
z=[y{:}];
size(z)
ans =

        1   584615
a.



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