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Octave's eval function
From: |
E. Joshua Rigler |
Subject: |
Octave's eval function |
Date: |
Thu, 20 Jan 2005 16:23:43 -0700 |
The following does what I want:
out=eval("if (~exist('tmp')) tmp=0; endif; tmp=tmp+1; tmp*5;");
...specifically, it evaluates the string to 1) initialize the variable
tmp if it doesn't already exist; 2) increment tmp by 1 each time it is
called; and 3) return tmp*5 to the variable out.
Is the fact that eval appears to always return the result of the last
expression in the string (i.e., tmp*5) strictly intentional? I can't
really tell from the help file. This is exactly what I want, but I just
want to be sure this behavior isn't likely to change anytime soon.
I'm running 2.1.64 with the latest Forge. Thanks,
EJR
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- Octave's eval function,
E. Joshua Rigler <=