Re: Finding peaks/max in a graph

[edA-qa mort-ora-y]

David Bateman wrote:
> A for-loop is not the way to go about this. Consider the code fragment
> n = 9
> a = [1 2 3 4 5 4 3 2 1]';
> peaks = find([a(2:n,1) - a(1:n-1,1) < 0; 1] & [1; a(1:n-1,1) - a(2:n,1) < 0]);
> that will find all indexes of the peaks in the data in a single statement

If you set
  a = [1 2 3 4 5 4 3 2 1 2 3 2 1]';
Peaks will only find 5, not the 3 as well.  I will see if somehow, 
however, I can modify my code not to use a for-loop, rather to use a 
similar notation to above.

--
edA-qa mort-ora-y
Idea Architect
http://disemia.com/



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