Re: Am I using varargin correctly?

[WJ Atsma]

Looks great. You can also use varargin{i} instead of nth(varargin,i).


On 2003.06.18 22:21 Jeff Sadowski wrote:
> function ans=nfactor(varargin)
>
> x=0;
> ans=[];
> while(x<nargin)
>  if(size(ans)!=0 || nth(varargin(x+1),1) != 0)
>   ans=[ans,nth(varargin(x+1),1)];
>  endif
>  x++;
> endwhile;
> ans=nfactor(ans);
> endfunction



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