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RE: LU decomposition/backsubstitution


From: John W. Eaton
Subject: RE: LU decomposition/backsubstitution
Date: Mon, 6 Dec 1999 14:04:40 -0600 (CST)

On  6-Dec-1999, Michael Hanke <address@hidden> wrote:

| One could use the LU decomposition [L,U]=lu(A), and
| then x=U\(L\b). This works efficiently if octave sees that L and U are
| triangular (at least after permutation). Does octave see this?

No, not yet.

jwe



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