Octave script question

[Andy Adler]

I'm writing a script to convert a file from jpg to
another utility, using octave.

here's the code 
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#!/usr/local/bin/octave -qf
   fn= argv(1,:);
   img= jpgread(fn); [m,n]= size(img);
   fwrite(stdout, [floor(m/256); rem(m,256);
                   floor(n/256); rem(n,256) ], 'uchar' );
   fwrite(stdout, img(:) ,'uchar');
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jpgread is a function that I wrote.

If I write to a file instead of stdout, then it works
fine, but if I call

sh>./scriptname jpgfile.jpg > jnkfile

then I only get 3 characters in jnkfile.
m=320;n=240; to the first 3 characters should be 1 64 0,
but instead they're 1 64 10.

If seems that some character (0) is acting as an EOF for
octave. Is that right?

Does the pager need to be disabled?
_____________________________________________________________________
Andy Adler      | American Biometric Company  | Tel:(613)736-5100x154
address@hidden | 3429 Hawthorne Rd,Ottawa,ON | Fax:(613)736-1348