[Bug 1896342] Re: IDE ATA IDENTIFY WORD 106

[Thomas Huth]

The QEMU project is currently moving its bug tracking to another system.
For this we need to know which bugs are still valid and which could be
closed already. Thus we are setting the bug state to "Incomplete" now.

If the bug has already been fixed in the latest upstream version of QEMU,
then please close this ticket as "Fix released".

If it is not fixed yet and you think that this bug report here is still
valid, then you have two options:

1) If you already have an account on gitlab.com, please open a new ticket
for this problem in our new tracker here:

    https://gitlab.com/qemu-project/qemu/-/issues

and then close this ticket here on Launchpad (or let it expire auto-
matically after 60 days). Please mention the URL of this bug ticket on
Launchpad in the new ticket on GitLab.

2) If you don't have an account on gitlab.com and don't intend to get
one, but still would like to keep this ticket opened, then please switch
the state back to "New" or "Confirmed" within the next 60 days (other-
wise it will get closed as "Expired"). We will then eventually migrate
the ticket automatically to the new system (but you won't be the reporter
of the bug in the new system and thus you won't get notified on changes
anymore).

Thank you and sorry for the inconvenience.


** Changed in: qemu
       Status: New => Incomplete

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https://bugs.launchpad.net/bugs/1896342

Title:
  IDE ATA IDENTIFY WORD 106

Status in QEMU:
  Incomplete

Bug description:
  The code at line 202 in hw/ide/core.c
   (https://git.qemu.org/?p=qemu.git;a=blob;f=hw/ide/core.c;#l201)
  hard codes bit 13 set.  However, get_physical_block_exp() can and may return 
0, which is a valid response. If get_physical_block_exp() does return zero, bit 
13 should not be set.

  ATAPI8 states (Section 7.17.7.73):
   "Bit 13 of word 106 shall be set to one to indicate that the device has more 
than one logical sector per physical sector"

  and gives the examples:
    Bits (3:0): 0 = 2^0 = 1 logical sector per physical sector
    Bits (3:0): 1 = 2^1 = 2 logical sector per physical sector
    Bits (3:0): 2 = 2^2 = 4 logical sector per physical sector
    Bits (3:0): 3 = 2^3 = 8 logical sector per physical sector

  Therefore, if bit 13 is set, bits 3:0 must be greater than zero.

  If get_physical_block_exp() returns zero then there is a 1:1 ratio and
  bit 13 must be 0.

  Just my opinion.

  Thanks,
  Ben

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