[Qemu-devel] [PATCH v4 1/8] qom: do not register interface "types" in the type table

[Alexey Kardashevskiy]

From: Paolo Bonzini <address@hidden>

There should be no need to look them up nor enumerate the interface
"types", whose "classes" are really just vtables.  Just create the
types and add them to the interface list of the parent type.

Signed-off-by: Paolo Bonzini <address@hidden>
Signed-off-by: Alexey Kardashevskiy <address@hidden>
---
 qom/object.c | 13 ++++++++++---
 1 file changed, 10 insertions(+), 3 deletions(-)

diff --git a/qom/object.c b/qom/object.c
index fc19cf6..3a43186 100644
--- a/qom/object.c
+++ b/qom/object.c
@@ -88,7 +88,7 @@ static TypeImpl *type_table_lookup(const char *name)
     return g_hash_table_lookup(type_table_get(), name);
 }
 
-static TypeImpl *type_register_internal(const TypeInfo *info)
+static TypeImpl *type_new(const TypeInfo *info)
 {
     TypeImpl *ti = g_malloc0(sizeof(*ti));
     int i;
@@ -122,8 +122,15 @@ static TypeImpl *type_register_internal(const TypeInfo 
*info)
     }
     ti->num_interfaces = i;
 
+    return ti;
+}
+
+static TypeImpl *type_register_internal(const TypeInfo *info)
+{
+    TypeImpl *ti;
+    ti = type_new(info);
+
     type_table_add(ti);
-
     return ti;
 }
 
@@ -216,7 +223,7 @@ static void type_initialize_interface(TypeImpl *ti, const 
char *parent)
     info.name = g_strdup_printf("%s::%s", ti->name, info.parent);
     info.abstract = true;
 
-    iface_impl = type_register(&info);
+    iface_impl = type_new(&info);
     type_initialize(iface_impl);
     g_free((char *)info.name);
 
-- 
1.8.4.rc4