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From: | Wenchao Xia |
Subject: | Re: [Qemu-devel] Are there plans to achieve ram live Snapshot feature? |
Date: | Tue, 13 Aug 2013 10:53:23 +0800 |
User-agent: | Mozilla/5.0 (Windows NT 5.1; rv:17.0) Gecko/20130801 Thunderbird/17.0.8 |
δΊ 2013-8-12 19:33, Stefan Hajnoczi ει:
On Mon, Aug 12, 2013 at 12:26 PM, Alex Bligh <address@hidden> wrote:--On 12 August 2013 11:59:03 +0200 Stefan Hajnoczi <address@hidden> wrote:The idea that was discussed on address@hidden uses fork(2) to capture the state of guest RAM and then send it back to the parent process. The guest is only paused for a brief instant during fork(2) and can continue to run afterwards.How would you capture the state of emulated hardware which might not be in the guest RAM?Exactly the same way vmsave works today. It calls the device's save functions which serialize state to file. The difference between today's vmsave and the fork(2) approach is that QEMU does not need to wait for guest RAM to be written to file before resuming the guest. Stefan
I have a worry about what glib says: "On Unix, the GLib mainloop is incompatible with fork(). Any program using the mainloop must either exec() or exit() from the child without returning to the mainloop. " There is another way to do it: intercept the write in kvm.ko(or other kernel code). Since the key is intercept the memory change, we can do it in userspace in TCG mode, thus we can add the missing part in KVM mode. Another benefit of this way is: the used memory can be controlled. For example, with ioctl(), set a buffer of a fixed size which keeps the intercepted write data by kernel code, which can avoid frequently switch back to user space qemu code. when it is full always return back to userspace's qemu code, let qemu code save the data into disk. I haven't check the exactly behavior of Intel guest mode about how to handle page fault, so can't estimate the performance caused by switching of guest mode and root mode, but it should not be worse than fork(). -- Best Regards Wenchao Xia
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