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Re: [PATCH] iscsi: Don't access non-existent scsi_lba_status_descriptor
From: |
Kevin Wolf |
Subject: |
Re: [PATCH] iscsi: Don't access non-existent scsi_lba_status_descriptor |
Date: |
Fri, 24 Jan 2020 14:45:04 +0100 |
User-agent: |
Mutt/1.12.1 (2019-06-15) |
Am 23.01.2020 um 21:37 hat John Snow geschrieben:
> On 1/23/20 12:05 PM, Kevin Wolf wrote:
> > In iscsi_co_block_status(), we may have received num_descriptors == 0
> > from the iscsi server. Therefore, we can't unconditionally access
> > lbas->descriptors[0]. Add the missing check.
> >
> > Signed-off-by: Kevin Wolf <address@hidden>
> > ---
> > block/iscsi.c | 2 +-
> > 1 file changed, 1 insertion(+), 1 deletion(-)
> >
> > diff --git a/block/iscsi.c b/block/iscsi.c
> > index cbd57294ab..c8feaa2f0e 100644
> > --- a/block/iscsi.c
> > +++ b/block/iscsi.c
> > @@ -753,7 +753,7 @@ retry:
> > }
> >
> > lbas = scsi_datain_unmarshall(iTask.task);
> > - if (lbas == NULL) {
> > + if (lbas == NULL || lbas->num_descriptors == 0) {
> > ret = -EIO;
> > goto out_unlock;
> > }
> >
>
> Naive question: Does the specification allow for such a response? Is
> this inherently an error?
Even if iscsi allowed it, it would be a useless response, because it
means that you didn't get the block status of any block.
bdrv_co_block_status() may only return *pnum == 0 at EOF, so I don't
think we have any other option than returning an error. (We could retry,
but if a target returns a useless response once, why should we trust it
do behave better the second time?)
> Anyway, this is better than accessing junk memory, so:
>
> Reviewed-by: John Snow <address@hidden>
Thanks!
Kevin