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[Paparazzi-devel] Paparazzi Convention for Euler Angles
From
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Avinash Rao
Subject
:
[Paparazzi-devel] Paparazzi Convention for Euler Angles
Date
:
Wed, 15 Feb 2012 13:48:47 +1300
Hi all,
I'm trying to understand the convention used for calculating Euler angles in paparazzi and how they relate to the drift correction in the AHRS.
From looking through the code for determining Euler angles from gravity and magnetometer, it would seem that the conventions is such that:
x_earth = R(psi)*R(theta)*R(phi)*x_body
i.e. the rotation R(psi)*R(theta)*R(phi) will transform a vector x measured in the body frame (e.g the gravity vector) back into the earth frame.
Is this correct or have I made a mistake somewhere?
Thanks very much for your help in advance.
Avinash.
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Avinash Rao
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[Paparazzi-devel] Paparazzi Convention for Euler Angles
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Avinash Rao
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Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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antoine drouin
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2012/02/14
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
,
Avinash Rao
,
2012/02/14
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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Christophe De Wagter
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2012/02/15
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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Avinash Rao
,
2012/02/15
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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Christophe De Wagter
,
2012/02/16
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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Felix Ruess
,
2012/02/16
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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Avinash Rao
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2012/02/19
Re: [Paparazzi-devel] Paparazzi Convention for Euler Angles
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Thomas Würfl
,
2012/02/15
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