Re: undefined compound chaining behavior

[John W. Eaton]

On 06/13/2014 12:52 PM, Mike Miller wrote:

> I would prefer option 1, add a note to the manual similar to what I
> suggested earlier in this thread, something along the lines of
>
> ---
>    An expression of the form
>
>         EXPR1 OP= EXPR2
>
>    is evaluated as
>
>         EXPR1 = (EXPR1) OP (EXPR2)
>
>    as long as EXPR2 is a simple expression with no side effects. If EXPR2
>    also contains an assignment operator, then this expression is
>    evaluated as
>
>         temp = EXPR2
>         EXPR1 = (EXPR1) OP temp
>
>    where 'temp' is a placeholder temporary value storing the computed
>    result of evaluating EXPR2.

This description looks good to me and also has the advantage of being 
the simplest change.  :-)

jwe