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Re: How to output stdout and stderr from an exec program script in monit

From: Russell Simpkins
Subject: Re: How to output stdout and stderr from an exec program script in monit
Date: Mon, 8 Feb 2016 15:22:14 -0500

I created

raise ValueError("throwing up")

I ran it by running 

$> python > /dev/null 2>&1
$> echo $?

Not sure what else you might be doing wrong

On Mon, Feb 8, 2016 at 3:13 PM, Vikram Kone <address@hidden> wrote:
For testing it I simply did this in the python script

raise ValueError("throwing up")

On Mon, Feb 8, 2016 at 10:39 AM, Russell Simpkins <address@hidden> wrote:

You don't show your python. Are you using "exit(1)" in your python when there is an error condition?
You need to exit(1) or something other than zero.


On Mon, Feb 8, 2016 at 1:06 PM, Vikram Kone <address@hidden> wrote:
I have a python script that I use as to check certain system conditions to alert on using monit.
This script prints a buch of stuff during execution to stdout which I want to capture in a log file.
How should I configure the monit conf script, such that I can capture both the stdout and stderr of this script and at the same time alerting on the exit status of the script. The monit alert should also included the stdout/stderr for the alert events.

This is what I tried


check program my_program with path "/usr/bin/python -u /opt/program/ > my_prgoram.log 2&>1"
 if status !=0 alert

But I see that the monit always thinks that the program is reporting status=0 even when then it exists with error code 1.

What am i doing wrong?

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