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Re: start program only works with "wrapper" script


From: Martin Pala
Subject: Re: start program only works with "wrapper" script
Date: Tue, 5 May 2015 13:12:11 +0200

Hi,

please try to run Monit in debug mode:

        1.) stop monit

        2.) start it in debug mode:

                monit -v

        3.) try to start the service:

                monit start wbm003

        4.) collect output from the logfile

Regards,
Martin


> On 04 May 2015, at 18:55, johng <address@hidden> wrote:
> 
> 
> hi all,
> 
> so we are running monit version:
> 
> /usr/bin/monit -V
> This is Monit version 5.12.2
> Copyright (C) 2001-2015 Tildeslash Ltd. All Rights Reserved.
> 
> on:
> 
> cat /etc/redhat-release
> Red Hat Enterprise Linux Server release 5.6 (Tikanga)
> 
> and it is pretty cool!  it is allowing us to monitor the application health 
> of some java tomcat applications we have through calling some curl checks we 
> have in a bash script.
> 
> what is not quite working correctly is the start aspect of the program. 
> sometimes it starts, sometimes it doesn't, sometimes it brings up java/tomcat 
> but certain aspects of the application don't work.  quite puzzling... i have 
> been looking at logs, writing wrapper scripts and googling extensively but 
> have not come to a definitive reason as to why the start program only works 
> when i preface it with a wrapper script.  any light you guys could shed on 
> this would be most welcome!  oh, also of note is that the "stop" program 
> facet of the monitrc file always works.  i can see the java/tomcat processes 
> disappear from the process list but it is the start that bombs.
> 
> our monitrc files look like so:
> 
> cat /etc/monitrc
> # /etc/monit.conf
> #
> 
> set daemon 60
> 
> set httpd port 2812
>    allow blah:bleh
>    allow localhost
>    allow xxx.xxx.xxx.xxx/24
> 
> set logfile /opt/company/log/monit/adm001
> 
> include /opt/company/etc/monit/*.monitrc
> 
> -------------------------------------
> 
> then the include file looks like so:
> 
> check process wbm003 with pidfile /var/run/jsvc1.pid
> 
> start program "/usr/bin/sudo /fusionone/bin/monit_wrapper.sh 
> /fusionone/bin/f1 -v start" with timeout 170 seconds
> 
> stop program "/usr/bin/sudo /fusionone/bin/monit_wrapper.sh /fusionone/bin/f1 
> -v stop" with timeout 170 seconds
> 
>  if not exist for 3 cycles then alert
> 
>        mode passive
> 
> check program wbm003_program with path "/fusionone/bin/check_wbm_cua.sh" with 
> timeout 10 seconds
>  if status != 0 then alert
> 
> --------------------------------------
> 
> the wrapper script is just this:
> 
> cat /fusionone/bin/monit_wrapper.sh
> #!/bin/sh
> {
>  echo "MONIT-WRAPPER date"
>  date
>  echo "MONIT-WRAPPER env"
>  env
>  echo "MONIT-WRAPPER $@"
>  $@
>  R=$?
>  echo "MONIT-WRAPPER exit code $R"
>  echo "MONIT-WRAPPER --------------------------------------------"
> } >>/tmp/monit.log 2>&1
> 
> ---------------------------------------
> 
> but what i don't understand is if i get rid of the wrapper script in the 
> start program, the program does not start or only partially starts.
> 
> so this doesn't work:
> 
> start program "/usr/bin/sudo /fusionone/bin/f1 -v start" with timeout 170 
> seconds
> 
> but this does:
> 
> start program "/usr/bin/sudo /fusionone/bin/monit_wrapper.sh 
> /fusionone/bin/f1 -v start" with timeout 170 seconds
> 
> -----------------------------------------
> 
> thank you,
> 
> baffled in seattle.
> 
> 
> 
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