Re: Not understanding 'Program Status Testing'

[Paul Theodoropoulos]

On 7/23/14 1:06 PM, Paul Theodoropoulos wrote:
> Which is all great - except that it never generates an alert! I've 
> confirmed that my other checks generate alerts - only this one fails 
> to do so.  I have of course tried reversing the status checks, etc - 
> no joy. So I'm still stuck.
I see the following in my daemon logs as the monitor is run:

Jul 23 13:29:41 localhost monit[1304]: 'bucardo.monitor' status succeeded
Jul 23 13:30:41 localhost monit[1304]: 'bucardo.monitor' 
'/usr/local/bin/bucardo.monitor.sh' failed with exit status (0) -- no 
output from program
Jul 23 13:31:01 localhost monit[1304]: 'bucardo.monitor' 
'/usr/local/bin/bucardo.monitor.sh' failed with exit status (0) -- no 
output from program

The exit status is what I expect, but this seems as if monit is 
complaining  about the expected exit status of zero - my failure status. 
So, I reversed the exit output as a test -

#!/bin/sh
/usr/local/bin/bucardo.pl status |/bin/grep trumgr|/usr/bin/cut -d"|" 
-f4|/bin/grep ".m" >/dev/null 2>&1
STATUS=$?
if [ "${STATUS}" -eq "1" ];then
    exit 0
else
    exit 1
fi

But still no joy:

Jul 23 13:37:39 localhost monit[1304]: 'bucardo.monitor' 
'/usr/local/bin/bucardo.monitor.sh' failed with exit status (1) -- no 
output from program
Jul 23 13:37:59 localhost monit[1304]: 'bucardo.monitor' 
'/usr/local/bin/bucardo.monitor.sh' failed with exit status (1) -- no 
output from program
Jul 23 13:38:19 localhost monit[1304]: 'bucardo.monitor' 
'/usr/local/bin/bucardo.monitor.sh' failed with exit status (1) -- no 
output from program

I'd be awfully surprised if I've found a bug, but I'm fully at a loss at 
this point.

--
Paul Theodoropoulos
www.anastrophe.com