Re: Syntax error trying to check program on php script

[Paspao]

Hello Martin,

You are right , in this server I have an older version.

Thank you !

P

Il giorno 08/mag/2014, alle ore 17:23, Martin Pala <address@hidden> ha scritto:

Hello,

what Monit version it is? The "check program" was added in Monit 5.3.

Regards,

Martin

On 08 May 2014, at 16:16, Paspao <address@hidden> wrote:

Hello,

I want to monitor a PHP script but I get a Sytax error .

This is the monit script:

check program test with path "/home/user/test.php"

        if status != 0 then alert 

I always get 

/etc/monit/monitrc:23: Error: syntax error 'test'

test.php is executable and contains :

#!/usr/bin/php -q

<?php

$err=1 ;

if($err != 0) exit(1);

?> 

If I run it in shell I get the correct $? of 0 or 1

Anyone knows how to solve this?

Thank you

P. 

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