[monit] Re: File check with execution of a script

[Julian Thomé]

Hi,
thank you for the fast answer.
I have written a little script, which examines the existence of 3 files 
but i don't understand the output.

Szenario:
I have 3 checks MNT, MNTDEP, MNTDEPDEP
and MNT depends on MNTDEP and MNTDEP depends on MNTDEPDEP.

my monitrc- file
----------------------
# alle n Sekunden sollen die Dienste überprüft werden
set daemon 300
#Mailserver für Benachrichtigungen
set mailserver localhost
# Absenderadresse der benachrichtigungen
set mail-format { from: address@hidden }
# Empfänger für die Benachrichtigungen
set alert address@hidden

set httpd port 28212 and
       allow localhost

set logfile /etc/monit/monit.log

check file MNT with path /etc/monit/monit.txt
       start program = "/etc/monit/monit.sh start"
       stop  program = "/etc/monit/monit.sh stop"
       depends on MNTDEP

check file MNTDEP with path /etc/monit/monit_dep.txt
       start program = "/etc/monit/monit_dep.sh start"
       stop program = "/etc/monit/monit_dep.sh stop"
       depends on MNTDEPDEP

check file MNTDEPDEP with path /etc/monit/monit_dep_dep.txt
       start program = "/etc/monit/monit_dep_dep.sh start"
       stop program = "/etc/monit/monit_dep_dep.sh stop"


here are the 3 shellscripts which should be executed if a file doesn' exist.

monit.sh

#!/bin/bash
case $1 in
       start)
               touch monit.txt
               echo "asdfasdfasdfasdf" > /etc/monit/monit.txt
               echo "monit start" >> /etc/monit/hier.txt
               ;;
       stop)
               echo "monit stop" >> /etc/monit/hier.txt
               ;;
esac


monit_dep.sh
----------------------
#!/bin/bash
case $1 in
       start)
               echo "asdfasdfasdfasdf" > /etc/monit/monit_dep.txt
               echo "monit_dep start" >> /etc/monit/hier.txt
               ;;
       stop)
               echo "monit_dep stop" >> /etc/monit/hier.txt
               ;;
esac

monit_dep_dep.sh
----------------------
#!/bin/bash
case $1 in
       start)
               echo "asdfasdfasdfasdf" > /etc/monit/monit_dep_dep.txt
               echo "monit_dep_dep start" >> /etc/monit/hier.txt
               ;;
       stop)
               echo "monit_dep_dep stop" >> /etc/monit/hier.txt
               ;;
esac

If for example the files monit_dep_dep.txt and monit_dep.txt doesnt 
exist in the monit.log (and here.txt) you can
see the following sequence:

monit stop
monit_dep_dep start
monit_dep start
monit start.

Could someone explain me why the start-file from MNTDEPDEP is executed. 
I really don't understand that, because the file monit_deb_deb.txt exists ?

Thank you very much
Julian Thomé











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