Hello,
I'm newbie for monit. Right now, monit monitors 2 processes due to the
configuration in monitrc file and it displays both process in the
terminal
window(when I use command "monit status"). Is it possible if I want
it to
display the result of just one process. I've tried with some
arguments but
it didn't work. Someone may think of this a stupid question, but your
suggestions will help me a lot. Thanks in advance for any help you can
offer.
PS. I've tried to separate them to different groups. But when I used
the
command "monit -g <group name> status", it still displays the status
of all
process.
AP
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