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| From: | Philip Guenther |
| Subject: | Re: flushing output in make |
| Date: | Mon, 17 Jul 2006 15:22:28 -0600 |
On 7/17/06, ma <address@hidden> wrote: ...
What I understand from your explanation on how make process a target is
that: . It first do all of the expanding. Assuming the following make file:
modules= a.o b.o c.o
mylib.lib: $(modules)
@echo starting...
$(foreach n, $(modules), $(shell $(AR) -qur $@ $(n)))
Make first expanding it to something such as this:
modules= a.o b.o c.o
mylib.lib: a.o b.o c.o
@echo starting...
$(AR) -qur $@ a.o
$(AR) -qur $@ b.o
$(AR) -qur $@ c.o
No. The the expansion of the $(shell) function is the output of the specified command, so all the $(AR) commands are being invoked while make is doing its expansion. Philip Guenther
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