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Re: bar lines at the beginning of staves
From: |
luis jure |
Subject: |
Re: bar lines at the beginning of staves |
Date: |
Sun, 18 Dec 2011 12:13:44 -0200 |
on 2011-12-18 at 14:39 David Kastrup wrote:
>Can you include the source for the example that does not yet do what you
>want? That way, it becomes much easier to be helpful.
again, i'm sorry i wasn't clear in the description of what i want. my
english is normally not very good, and it's even worse on cloudy sundays...
i tried to make clear what i wanted, hoping that someone could give me
some hints how to get it. examples of code that DON'T do what i do are
easy, for example the snippet sent by thomasmorley65:
\version "2.14.2"
<<
\new Staff { c'1 d' }
\new Staff { c'1 d' }
\new Staff { c'1 d' }
\new Staff { c'1 d' }
>>
here the line at the beginning of the group connects all the staves, while
i just want a line equivalent to a bar line at the beginning of each
staff (again, see the image i attached in the other message).
if i use \remove "System_start_delimiter_engraver", i can't get a bar line
at the beginning of the staff, even including \bar "|" before the music:
\version "2.14.2"
<<
\new Staff { \bar "|" c'1 d' }
\new Staff { \bar "|" c'1 d' }
\new Staff { \bar "|" c'1 d' }
\new Staff { \bar "|" c'1 d' }
>>
\layout {
\context {
\Score
\remove "System_start_delimiter_engraver"
}
}
thanks for your attention!
lj
- bar lines at the beginning of staves, luis jure, 2011/12/18
- Re: bar lines at the beginning of staves, Thomas Morley, 2011/12/18
- Re: bar lines at the beginning of staves, luis jure, 2011/12/18
- Re: bar lines at the beginning of staves, Marc Hohl, 2011/12/18
- Re: bar lines at the beginning of staves, luis jure, 2011/12/18
- Re: bar lines at the beginning of staves, Thomas Morley, 2011/12/18
- Re: bar lines at the beginning of staves, luis jure, 2011/12/18
- Re: bar lines at the beginning of staves, Thomas Morley, 2011/12/18
Re: bar lines at the beginning of staves, David Kastrup, 2011/12/18
- Re: bar lines at the beginning of staves,
luis jure <=