Re:substitution for numerator

[Stefan Thomas]

Dear Jan-Peter,
I would like to create a music function which allows You to build a slur lasting some eigth-triplet and some sixtheenth-quintuplet notes.
I dream of something like:

music = \relative c' {
 \times 2/3 {c8 d e } \times 4/5 {c16 a g f e } 
}
slurs = {
 \tripletquintupletslur #2 #5 % the slur lasts 2 triplet and 5 quintuplet notes
}
\new Staff { \context Voice << { \music} {\slurs }>>}
 %%%%%%%%%%
> > Hello Stefan,
> >
> > you probably have to code the scaled note in scheme:
> > --snip--
> > numerator = #(define-music-function (parser location x) (integer?)
> >    (make-music 'EventChord
> >      'elements
> >      (list
> >        (make-music 'NoteEvent
> >          'duration (ly:make-duration 0 0 3 x)
> >          'pitch (ly:make-pitch 0 0 0))
> > )))
> >
> > \displayMusic \relative c' {
> >    \numerator #4 c4
> > }
> > --snip--
> >
> > But you will get the same result, if you use the times-command:\times
> > 2/3 { c1 }
> > This will set the numerator and denominator in the duration. And if you
> > want to hide the tuplet bracket and number, you can do so with:
> >    \once \override TupletBracket #'stencil = ##f
> >    \once \override TupletNumber #'stencil = ##f
> >
> > But this is probably not the source of your question. What is your goal?
> >
> > Cheers,
> > Jan-Peter
> >
> >
> > Am 18.09.2011 11:01, schrieb Stefan Thomas:
> > > numerator = #(define-music-function (parser location x) (number?)
> > >   #{ % in der folgenden Zeile Lilypondcode eingeben
> > >     c1*$x/3
> > > #})
> > > themusic = {
> > >   \numerator #4
> > > }